0.4 g of an organic compound gave 0.188 g of silver bromide by a halogen estimation method. The percentage of bromine in the compound is (at. wts :of Ag=108, Br = 80)

Given data:It is given to calculate the percentage of bromine in the  organic compound .

Explanation:

Sol:

$\begin{array}{l}=\frac{80}{188}\times \frac{\text{ Mass of }\mathrm{AgBr}\times 100}{\text{ Mass of compound }}\\ =\frac{80}{188}\times \frac{0.188\times 100}{0.4}=\frac{8}{0.4}=20\%\end{array}$

Hence, the correct option is: (B) 20 %