0.5 g of an organic compound containing nitrogen on Kjeldahlising require 29 mL of N / 5 H2SO4 for complete neutralization of Ammonia. The percentage of nitrogen in the compound is:

Meq .of NH3 formed =29×15: Mass of NH3=295×171000g ∴ Mass of N2 in NH3=1417×29×175×1000g ∴ % of N=14×29×17×10017×5×1000×0.5=16.24

0.5 g of an organic compound containing nitrogen on Kjeldahlising require 29 mL of N / 5 H2SO4 for complete neutralization of Ammonia. The percentage of nitrogen in the compound is:

Meq .of NH3 formed =29×15: Mass of NH3=295×171000g ∴ Mass of N2 in NH3=1417×29×175×1000g ∴ % of N=14×29×17×10017×5×1000×0.5=16.24

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0.5 g of an organic compound containing nitrogen on Kjeldahlising require 29 mL of N / 5 H₂SO₄ for complete neutralization of Ammonia. The percentage of nitrogen in the compound is:

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14.8

34.3

16.2

21.6

answer is B.

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Detailed Solution

Meq .of NH₃ formed $= 29 \times \frac{1}{5}$ :
$Mass of {NH}_{3} = \frac{29}{5} \times \frac{17}{1000} g ∴ Mass of N_{2} in {NH}_{3} = \frac{14}{17} \times \frac{29 \times 17}{5 \times 1000} g ∴ % of N = \frac{14 \times 29 \times 17 \times 100}{17 \times 5 \times 1000 \times 0 .5} = 16 .24$