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Q.

0.5 gm of fuming $H_{2} {SO}_{4}$ (Oleum) is diluted with water. This solution is completely neutralised by 26.7 ml of 0.4 M $NaOH$ solution. Calculate the
percentage of free ${SO}_{3}$ in the given sample. Give your answer excluding the decimal places.

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answer is 20.

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Detailed Solution

$\frac{x}{40} + \frac{0.5 - x}{49} = \frac{26.7 \times 0.4}{1000}$

$\Rightarrow x = 0.1 g$

% free ${SO}_{3} = 20 %$ .

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0.5 gm of fuming H2SO4 (Oleum) is diluted with water. This solution is completely neutralised by 26.7 ml of 0.4 M NaOH solution. Calculate the percentage of free SO3 in the given sample. Give your answer excluding the decimal places.