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0.5 molal aqueous solution of a weak acid (HX) ·is ~0%
ionised. If K1 for water is 1.86K Kg mo/-1, the lowering in
freezing point of the solution is

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1.12 K

- 1.12 K

- 0.56 K

0.56 K

answer is C.

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Detailed Solution

$\begin{array}{l} α = \frac{i - 1}{n - 1} \Rightarrow 0.2 = \frac{i - 1}{2 - 1} \Rightarrow i = 1.2 \\ \Rightarrow Δ T = i \times K_{f} \times m \end{array}$

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