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Q.

0.5 molal NaCl and 0.8 molal urea solutions are formed to be isotonic at 27° C then the degree of dissociation of NaCl under these conditions is reported as x × 10%. What is the value of ‘x’ ?

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answer is 6.

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Detailed Solution

π1=π2NaCli×0.5=  Urea i=85=1.6;α=i−1n−1=1.6−12−1=0.6x×10%=60%⇒x=6

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