0.5 mole of each H₂ ,SO₂and CH₄ are kept in a container. A hole was made in the container after 3 hours decreasing order of partial pressures of gases in the container will be

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$P_{{SO}_{2}} > P_{{CH}_{4}} > P_{H_{2}}$

$P_{H_{2}} > P_{{SO}_{2}} > P_{{CH}_{4}}$

$P_{{CH}_{4}} > P_{{SO}_{2}} > P_{H_{2}}$

$P_{{CH}_{4}} > P_{H_{2}} > P_{{SO}_{2}}$

answer is A.

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Detailed Solution

$Rate of diffusion \propto \frac{1}{Molar mass (or) no . of moles}$

So that no. of moles of SO₂ is least diffused than CH₄ than H₂

$∴$ $P_{{SO}_{2}} > P_{{CH}_{4}} > P_{H_{2}}$

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