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0.6 mole of PCl_5,0.3 mole of PCl₃and 0.4 mole of Cl₂ are taken in a 1 L flask to obtain the following equilibrium ${PCl}_{5} (g) ⇌ {PCl}_{3} (g) + {Cl}_{2} (g)$ . If the equilibrium constant K_c for the reaction is 0.15. Predict the direction of the reaction.

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Direction of the reaction cannot be predicted

Backward direction

Forward direction

Reaction does not move in any direction

answer is B.

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Detailed Solution

${PCl}_{5} (g) ⇌ {PCl}_{3} (g) + {Cl}_{2} (g)$
$\begin{array}{l} Q_{c} = \frac{0 .4 \times 0 .3}{0 .6} = 0 .2 \\ K_{c} = 0 .15 \end{array}$
Since, $Q_{c} > K_{c}$ reaction will proceed in backward direction.

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