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Q.

$0.6 mol$ of barium chloride in solution is mixed with 0.2 mol of sodium phosphate, the amount of barium phosphate produced is :

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a

0.1 mol

b

0.4 mol

c

0.3 mol

d

0.5 mol

answer is A.

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Detailed Solution

In the given reaction we have,

1 mole ${Na}_{3} \overset{}{\overset{}{P_{4}}} \to \frac{1}{2}$ ${Ba}_{3} {{(PO}_{4})}_{2}$

0.2 mole ${Na}_{3} {PO}_{4} \to \frac{1}{2} \times 0.2 = 0.1 mole$

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