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0.72gm of an oxide of a metal M on reduction with H₂ gave 0.64g of the metal. The atomic weight of the metal is 64. The empirical formula of the compound is

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M₂O

MO₂

M₂O₃

answer is B.

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Detailed Solution

Weight of metal oxide = 0.72g

Weight of metal = 0.64g

Weight of Oxygen = 0.08g

$\large \frac{W_M}{E_{O_2}} = \frac{E_M}{E_{O_2}}$

$\large \frac{0.64}{0.08} = \frac{E_M}{8}$

E_M = 64

Atomic weight of metal = 64

Equivalent weight of metal = 64

$valency\;=\;\large \frac{64}{64} = 1$

Valency of metal = 1

Valency of Oxygen = 2

Criss-Cross method

Formula of the metal oxide is M₂O

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