Q.

0.75 g of a sample of pyrolusite ore is treated with 1.89 g of oxalic acid crystals H2C2O4.2H2O in acidic medium to analyze for its  MnO2 content. Following the reaction, the excess oxalic acid is titrated with 0.100 M KMnO4 under acidic conditions, 30.00 mL being required. The percentage of Mn in the ore is______. (Atomic weights: Mn = 55 u)

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!
An Intiative by Sri Chaitanya

answer is 55.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

detailed_solution_thumbnail

MnO2 +C2O42+4H+ 2Mn2++2CO2+2H2O

2MnO4+5C2O42+16H+ 2Mn2++10CO2+8H2O

2×nC2O42(unused)=5×nMnO42×x=5×0.1×30.01000x=7.5×103mol

nC2O42used)=1.891267.5×103=7.5×103=nMn(in pyrolusite)% of Mn=7.5×103×550.75×100=55%

Watch 3-min video & get full concept clarity

hear from our champions

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon