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0.84 g, of an acid of Molecular weight 225 is present in 100ml of the solution. 25ml of this solution required 28 ml of N/10 NaOH solution for complete neutralisation. The basicity of the acid is

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answer is C.

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Detailed Solution

Acid NaOH(base)

V_a =25ml V_b = 28ml

N_a =? N_b = 0.1N

equivalency

V_aN_a = V_bN_b

25(N_a) = 28(0.1)

$N_a=\frac{2.8}{25}$

Given , W_a = 0.84g , GMW of acid =225g

V_sol = 100ml

$\therefore N=\frac{W}{GEW}X\frac{1000}{V(ml)}$

$\frac{2.8}{25}=\frac{0.84}{GEW}X\frac{1000}{100}$

EW of acid =75g

MW of acid = 225g

$Basicity\; of\; acid =\frac{225}{75}=3$

Hence the correct answer is (C)3

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