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Q.

λ1,λ2  and   λ3 are the wavelength for a proton, deuteron and alpha particle accelerating through a potential difference of 100V. The ratio of their de-Broglie wavelengths is

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a

1:2:2

b

1:2:2

c

2:2:1

d

22:2:1

answer is D.

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Detailed Solution

λ=h2qvm⇒λ∝1qm

⇒λ1:λ2:λ3=1qpmp:1qm0:1qαmα

=1(1)(1):1(2)(2):12×4

=22:2:1

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