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1.44 gm of titanium ( At mass : 48) reacted with excess of $O_{2}$ and produce X gms of non Stoichiometry compound $T i_{1.44} O$ the value of X is

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1.44

3.54

1.77

answer is B.

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Detailed Solution

$T i + O_{2} \to T i_{1.44} O$

$\frac{1.44}{48} m o l e \frac{x}{48 (1.44) + 16} m o l e$

$\frac{1.44}{48} = \frac{x}{48 (1.44) + 16} \Rightarrow x = 1.77 g m$

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