$1) {49}^{\mathrm{n}}+16\mathrm{n}-1$ is divisible by A for all $\mathrm{n}\in \mathrm{N}$

$2) 3^{2\mathrm{n}}+7$ is divisible by B for all $\mathrm{n}\in \mathrm{N}$

$3) 4^{\mathrm{n}}-3\mathrm{n}-1$ is divisible by C for all $\mathrm{n}\in \mathrm{N}$

$4) 3^{3\mathrm{n}}-26\mathrm{n}-1$ is divisible by D for all $\mathrm{n}\in \mathrm{N}$ 

then the increasing order of A, B, C, D is

1)  $\mathrm{P}\left(\mathrm{n}\right)={49}^{\mathrm{n}}+16\mathrm{n}-1$ is divisible by 64

2)  $$\begin{gathered} \mathrm{P}\left(\mathrm{n}\right)=3^{2\mathrm{n}}+7 \\ \mathrm{P}\left(1\right)=9+7=16 \\ \mathrm{P}\left(2\right)=3^4+7=81+7=88 \end{gathered}$$

     $\mathrm{P}\left(\mathrm{n}\right)$ is divisible by 8

3)  $$\begin{gathered} \mathrm{P}\left(\mathrm{n}\right)=4^{\mathrm{n}}-3\mathrm{n}-1 \\ \mathrm{P}\left(1\right)=4-3-1=0 \\ \mathrm{P}\left(2\right)=16-6-1=9 \end{gathered}$$

     $\mathrm{P}\left(\mathrm{n}\right)$ is divisible by 9

4)  $$\begin{gathered} 3^{3\mathrm{n}}-26\mathrm{n}-1=\mathrm{P}\left(\mathrm{n}\right) \\ \mathrm{P}\left(1\right)=27-26-1=0 \\ \mathrm{P}\left(2\right)=729-72-1=676 \end{gathered}$$

      is divisible by 676