1.5 moles of an ideal non – linear polyatomic gas changes its state from state A (12.45 bar, 2 L) to state B (5 L, 300 K) through an isobaric process.
(Given : $C_{p, m} o f g a s = 4 R, R = 8.3 J K^{- 1} m o l^{- 1} = 0.083 b a r . L K^{- 1} m o l^{- 1}$ )
Which of the following change in thermodynamic property is rightly indicated?

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$Δ U_{A B} = 3735 J$

$P_{B} = 12.45 a t m$

$T_{A} = 200 K$

$Δ H_{A B} = 4980 J$

answer is A, B, D.

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Detailed Solution

$T_{A} = \frac{12.45 \times 2}{1.5 \times 0.083} = 200 K, P_{B} = 12.45 b a r Δ H_{A B} = 1.5 \times 4 R \times 100 = 600 R = 600 \times 8.3 = 4980 J Δ U_{A B} = 4980 - (37.35 - 24.9) 100 J = 3735 J$

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