1 ampere current is equivalent to

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$2 .25 \times 10^{18}$ electrons s^-1

$6 .25 \times 10^{14}$ electrons s^-1

$6 .25 \times 10^{18}$ electrons s^-1

$2 .25 \times 10^{14}$ electrons s^-1

answer is A.

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Detailed Solution

$q = i . t = n . e \Rightarrow \frac{n}{t} = \frac{i}{e} \Rightarrow \frac{n}{t} = \frac{1}{1 .6 \times 10^{- 19}} = 6 .25 \times 10^{18} electronics s^{- 1}$

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