1 atom of X, 2 atoms of Y and 3 atoms of Z combine together to give a molecule XY2Z3• Now we take 10 gm of X and 2×1023 atoms of Y and 0.06 moles of Z in a container, to give 5.6 gm of XY2Z3• What is the molar mass of Z?

We have given that,nX=1060; X=16nY=2×10236×1023; nY=13nZ=0.06X+2Y+3Z→XY2Z316 16 0.02 0.02 moles 0.02×[60+160+3z]=5.6⇒Z=20

1 atom of X, 2 atoms of Y and 3 atoms of Z combine together to give a molecule XY2Z3• Now we take 10 gm of X and 2×1023 atoms of Y and 0.06 moles of Z in a container, to give 5.6 gm of XY2Z3• What is the molar mass of Z?

We have given that,nX=1060; X=16nY=2×10236×1023; nY=13nZ=0.06X+2Y+3Z→XY2Z316 16 0.02 0.02 moles 0.02×[60+160+3z]=5.6⇒Z=20

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1 atom of X, 2 atoms of Y and 3 atoms of Z combine together to give a molecule ${XY}_{2} Z_{3}$ • Now we take 10 gm of X and $2 \times 10^{23}$ atoms of Y and 0.06 moles of Z in a container, to give 5.6 gm of ${XY}_{2} Z_{3}$ • What is the molar mass of Z?

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Detailed Solution

We have given that,

$n_{X} = \frac{10}{60};_{X} = \frac{1}{6}$

$n_{Y} = \frac{2 \times 10^{23}}{6 \times 10^{23}}; n_{Y} = \frac{1}{3}$

$n_{Z} = 0.06$

$\begin{array}{l} X + 2 Y + 3 Z \to {XY}_{2} Z_{3} \\ \frac{1}{6} \frac{1}{6} 0.02 0.02 moles \end{array}$

$\begin{array}{l} 0.02 \times [60 + 160 + 3 z] = 5.6 \\ \Rightarrow Z = 20 \end{array}$

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1 atom of X, 2 atoms of Y and 3 atoms of Z combine together to give a molecule XY2Z3• Now we take 10 gm of X and 2×1023 atoms of Y and 0.06 moles of Z in a container, to give 5.6 gm of XY2Z3• What is the molar mass of Z?

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1 atom of X, 2 atoms of Y and 3 atoms of Z combine together to give a molecule ${XY}_{2} Z_{3}$ • Now we take 10 gm of X and $2 \times 10^{23}$ atoms of Y and 0.06 moles of Z in a container, to give 5.6 gm of ${XY}_{2} Z_{3}$ • What is the molar mass of Z?