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Q.

$1 -$ butyne reacts with cold alkaline ${KMnO}_{4}$ to produce

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a

${CH}_{3} {CH}_{2} {CH}_{2} COOH$

b

${CH}_{3} {CH}_{2} COOH$

c

${CH}_{3} {CH}_{2} COOH + {CO}_{2}$

d

${CH}_{3} {CH}_{2} COOH + HCOOH$

answer is C.

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Detailed Solution

${CH}_{3} - {CH}_{2} - C \equiv CH \to_{alk {KMnO}_{4}}^{Cold} {CH}_{3} {CH}_{2} COOH + {CO}_{2}$

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