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Q.

1 g of a mixture of NaHCO3 and Na2CO3 is heated to 150° C . The volume of the CO2 produced at STP is 112.0 mL. Calculate the percentage of Na2CO3 in the mixture (Na = 23, C=12,O =16)

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a

16

b

20

c

46

d

84

answer is D.

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Detailed Solution

2NaHCO3⟶150∘CNa2CO3+CO2+H2O
nNaHCO3nCO2=21
nNaHCO3=2nCO2
=2×11222400=0.01mole
WNaHCO3=0.01×84=0.84g
WNa2CO3=1.00−0.84=0.16g
%Na2CO3=16

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