1 g of I2 is in 10 mL CHCI3. When 400 mL H2O is added into it, concentration of I2 in CHCI3 falls to 0.80 g. Hence, partition coefficient of I2 in CHCI3 and H2O is

I2 present in 10mLCHCl3=0.8g I2 extracted into 400mLH2O=0.2g∴ CI2CHCl3=0.810gmL−1CT2H2O=0.2400gmL−1∴ CI2CHCl3CI2H2O=0.8100.2400=160

1 g of I2 is in 10 mL CHCI3. When 400 mL H2O is added into it, concentration of I2 in CHCI3 falls to 0.80 g. Hence, partition coefficient of I2 in CHCI3 and H2O is

I2 present in 10mLCHCl3=0.8g I2 extracted into 400mLH2O=0.2g∴ CI2CHCl3=0.810gmL−1CT2H2O=0.2400gmL−1∴ CI2CHCl3CI2H2O=0.8100.2400=160

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1 g of I₂ is in 10 mL CHCI₃. When 400 mL H₂O is added into it, concentration of I₂ in CHCI₃falls to 0.80 g. Hence, partition coefficient of I₂ in CHCI₃ and H₂O is

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$I_{2} present in 10 mL {CHCl}_{3} = 0 .8 g I_{2} extracted into 400 {mLH}_{2} O = 0 .2 g$

$∴ C_{I_{2}} ({CHCl}_{3}) = \frac{0 .8}{10} g {mL}^{- 1}$

$C_{T_{2}} (H_{2} O) = \frac{0 .2}{400} g {mL}^{- 1}$

$∴ \frac{C_{I_{2}} ({CHCl}_{3})}{C_{I_{2}} (H_{2} O)} = \frac{\frac{0 .8}{10}}{\frac{0 .2}{400}} = 160$

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1 g of I2 is in 10 mL CHCI3. When 400 mL H2O is added into it, concentration of I2 in CHCI3 falls to 0.80 g. Hence, partition coefficient of I2 in CHCI3 and H2O is

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1 g of I₂ is in 10 mL CHCI₃. When 400 mL H₂O is added into it, concentration of I₂ in CHCI₃falls to 0.80 g. Hence, partition coefficient of I₂ in CHCI₃ and H₂O is