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Q.

1 g of the carbonate of a metal was dissolved in 25 mL of N-HCI. The resulting liquid required 5 mL of N-NaOH for neutralisation. The Ew of the metal carbonate is

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a

50

b

20

c

None

d

30

answer is A.

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Detailed Solution

HCl⇒25×1=25 m Eq  Excess HCl⇒5×1=5 m Eq  HCl used ⇒25−5=20 m Eq ∴m Eq of HCl=m Eq of carbonate 

201000Eq= Weight Ew of carbonate =1Ew∴Ew=100020=50

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