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1 gram of activated charcoal is added to 500 ml of 0.2 M oxalic acid aqueous solution. After some time the concentration of the solution is found out to be 0.1M. Then amount of crystalline oxalic acid adsorbed on 1 gram of charcoal is

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12.6 g

8 g

6.3 g

4 g

answer is C.

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Detailed Solution

$0.2 M = \frac{w L}{126} \times \frac{1000}{500} ∴ w L = 12.6 g [i n i t i a l l y]$

$0.1 M = \frac{w L}{126} \times \frac{1000}{500} ∴ w L = 6.3 g [F i n a l]$

$∴$ oxalic acid adsorbed = 12.6 – 6.3

= 6.3 g

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