1 gram of steam at 100°C is passed into an insulating veesal having 1gram of ice at 0°C Find the equilibrium temperature of the mixture ...
(neglecting heat capacity of the vessel)

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180°C

100°C

0°C

100°F

answer is B.

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Detailed Solution

heat available on steam $= 1 \times 540 = 540 Cal$
Heat gained by ice to attain $100^{0} C = 1 \times 80 + 1 \times 1 \times (100 - 0) = 180 Cal$
$∴$ final temperature of the mixture = 100°C

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