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[[1]] is the area of the following figure.

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Detailed Solution

First, we have a rectangle:

Length = 8 cm
Breadth = 5 cm
Next, we have a trapezium:

Height = 5 cm
Side 1 = 7 cm
Side 2 = 6 cm
The last shape we have is a parallelogram:

Base = 7 cm
Height = 5 cm
So, the area of figure = area of rectangle + area of trapezium + area of parallelogram
(i.e)

A = A R + A T + A P ...... (1)

As we know that: Area of rectangle:

A R = l × b

So, we have

A R = 8 × 5 A R = 40 c m 2 ......... (2)

s
Area of trapezium:

A T = 12 × sum of parallel sides × height

So, we have:

A T = 12 × (7 + 6) × 5 A T = 32.5 c m 2 ...... (3)

Area of parallelogram:

A P = 12 × base × height

Since,

A P = 12 × 7 × 5 A P = 17.5 c m 2 ...... (4)

Adding all equations to get the area of the given figure,
The area of the figure is,

A = 40 + 32.5 + 17.5 A = 90 c m 2

Hence, the area of figure is

90 c m 2

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