[[1]] is the largest number which divides 615 and 963 leaving the remainder 6 in each case.

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Detailed Solution

Given,
To find the largest number which divides 615 and 963 leaving a remainder 6 in each other.
So, subtract 6 from 615 and 963
615 – 6 = 609
963 - 6 = 957
Finding HCF using prime factorization,
609 = 29 × 3 × 3
957 = 29 × 11 × 3
Considering the common factors, that is 29 and 3.
x = 29 × 3 = 87
87 is the largest number which divides 615 and 963 leaving the remainder 6 in each case.

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