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Q.

1 kg water of specific heat 1 cal/gm-0C is kept in a container at 100C. If  500 gm of ice at 00C is required to cool down the water from 100C to 00C, the water equivalent of container is  (Latent of fusion for ice = 80 cal/gm and specific heat of water is 1 cal/gm-0C)  

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a

1 kg

b

2 kg

c

3 kg

d

12kg

answer is C.

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Detailed Solution

(m+1000)×1×10=50×80 (m+1000)=4000 m=3000gm = 3 kg    (c)

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