1 L mixture of CO and ${\text{CO}}_{\text{2}}$ is taken. This is passed through a tube containing red hot charcoal.  The volume now becomes 1.6 litre. The volumes are measured under the same conditions.  Find the composition of mixture by volume

Let there be $x\text{\hspace{0.17em}\hspace{0.17em}m}L$ CO in the mixture, hence, there will  be $(1000-x)$ mL $C{O}_2$.  The reaction of $C{O}_2$ with red hot charcoal may be given as,

Total volume of the gas becomes          $=x+2(1000-x)$

$\begin{array}{c}x+2000-2x=1600\\ x=400mL\end{array}$

$\therefore$ Volume of CO=400 mL and volume of $C{O}_2=600mL$