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Q.

1 litre aqueous solution of H2SO4 contains 0.02 m mol H2SO4 ,50% of this solution is diluted with deionized water to give 1L solution (A). In solution (A) ,0.01 mmol of H2SO4 are added .Total m moles of  H2SO4 in the final solution is _______________ x 103 mmols.

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answer is 0.

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Detailed Solution

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no. of moles of  H2SO4 solution of A = 50% of the original solution = 0.01 m mol

no .of moles of  H2SO4 in final solution = 0.01 + 0.01=0.02

=0.02 = 0.00002 x 103

therefore answer is zero

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