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Q.

1 molal aqueous solution of an electrolyte AB2 is 80% ionized into A+2 and B-1 ions. The boiling point of the solution at 1 atm is:

KbH2O=0.5 K kg mol1

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a

100.5 K

b

374.3 K

c

373.5 K

d

274.3 K

answer is C.

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Detailed Solution

Here, values at different time,

                   AB2     A2+  +2B

t=0         1          0      0

t=t       1α         α       2α

nT=1+2αi=1+2×0.8=2.6ΔTb=iKbm=2.6×5×1=1.3Tb=373+1.3=374.3 K

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