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Q.

1 mole of an ideal gas expands from $5 {dm}^{3}$ to $25 {dm}^{3}$ isothermally and irreversibly at $27^{0} C$ . Find work done in the process $[R = 8 .3 J / mol / K]$

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a

$+ 1.99 KJ$

b

$- 7.46 KJ$

c

$+ 7.46 KJ$

d

$- 1.99 kJ$

answer is A.

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Detailed Solution

$\begin{array}{l} w = - P_{ext} (V_{2} - V_{1}) \\ = \frac{- 1 \times 8.3 \times 300}{25} \times \frac{[25 - 5]}{1000} \\ = - 1.99 kJ \end{array}$

$(∵ P_{ext} = P_{2})$

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1 mole of an ideal gas expands from 5dm3 to 25dm3 isothermally and irreversibly at 270C. Find work done in the process [R=8.3J/mol/K]