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1 mole of ${CH}_{4}$ contains

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$6 .02 \times 10^{23} atoms of H$

4 g atom of Hydrogen

$1.81 \times 10^{23} m o l e c u l e s o f C H_{4}$

3.0 g of carbon

answer is B.

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Detailed Solution

1 mole of ${CH}_{4}$ contains (1) 4 mole of hydrogen atom, i.e., 4 g atom of hydrogen.

(2) $4 \times 6.023 \times 10^{23}$ atoms of ‘H’

(3) $6.023 \times 10^{23}$ molecules of $C H_{4}$

(4) 12 gm of Carbon

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