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1 mole of equimolar mixture of ferric oxalate and ferrous oxalate will require x mole of $K M n O_{4}$ in acidic medium for complete oxidation, then ‘x’ is….

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4.5 mole

0.9 mole

1.2 mole

0.5 mole

answer is B.

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Detailed Solution

$3 m o l e K M n O_{4} = 5 m o l e F e C_{2} O_{4}$
$6 m o l e K M n O_{4} = 5 m o l e F e_{2} {(C_{2} O_{4})}_{3}$
$∴$ 1 mole equimolar mixture of $F e C_{2} O_{4}$ and $F e_{2} {(C_{2} O_{4})}_{3} = 0.9$ moles of $K M n O_{4}$

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