1 Mole of IO3− ions are heated with excess of I− ions in the presence of acidic conditions as per the following equation IO3−+I−→I2. How many moles of hypo solution will be required to react completely with I2 thus produced

10e−+2Io3−→I2 [2I−→I2+2e−]×5_ 2Io3−+10I−→6I2 I2+2S2O32−→S4O62−+2I− 1 mole Io3−= 5 moles I−=3 moles I2 ∴3 moles I2=6 moles S2O32−

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1 Mole of $I O_{3}^{-}$ ions are heated with excess of $I^{-}$ ions in the presence of acidic conditions as per the following equation $I O_{3}^{-} + I^{-} \to I_{2}$ . How many moles of hypo solution will be required to react completely with $I_{2}$ thus produced

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answer is 6.

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Detailed Solution

$10 e^{-} + 2 I o_{3}^{-} \to I_{2}$
$\underline{[2 I^{-} \to I_{2} + 2 e^{-}] \times 5}$
$2 I o_{3}^{-} + 10 I^{-} \to 6 I_{2}$
$I_{2} + 2 S_{2} O_{3}^{2 -} \to S_{4} O_{6}^{2 -} + 2 I^{-}$
1 mole $I o_{3}^{-} =$ 5 moles $I^{-} = 3$ moles $I_{2}$
$∴ 3 m o l e s I_{2} = 6 m o l e s S_{2} O_{3}^{2 -}$

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