1 mole of ${ }_7^{14}{N}^{-3}$ ions contains 

$7\times 6.023\times {10}^{23}neutrons$

$7 \times 6.023 \times {10}^{23}electrons$

$14\times 6.023\times {10}^{23}protons$

$7\times 6.023\times {10}^{23}protons$