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Q.

1.n + 2.(n – 1) + 3(n – 2) + ......... +(n – 1).2 + n.1 =

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a

n(n+1)(2n+1)6

b

n(n+1)(n+2)6

c

n(n2+1)2

d

n(n+1)2

answer is B.

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Detailed Solution

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tn=r(n+1-r) =(n+1)r-r2 =(n+1) n(n+1)2-n(n+1) (2n+1)6 =n(n+1)2 n+1-2n+13 =n(n+1)2 3n+3-2n-13 =n(n+1) (n+2)3

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