10 g of $C a C O_{3}$ is completely decomposed to X and CaO. X is passed into an aqueous solution containing one mole of sodium carbonate. What is the number of moles of sodium bicarbonate formed ? (Mol. Wts : $C a C O_{3}$ =100. $N a_{2} C O_{3}$ =106. $N a H C O_{3}$ =84)

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answer is 0.2.

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Detailed Solution

10g of $C a C O_{3} [M . w t . o f 100 g / m o l]$ correspond to 0.1 mol

They will give 1 mole of CaO and 1 mol of CO₂

$C a C O_{3} \to C a O + C O_{2}$

$N a_{2} C O_{3} + H_{2} O + C O_{2} \to 2 N a H C O_{3}$

$= \frac{16}{8} = 0.2 m o l$

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