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$10 g$ of Calcium carbonate contains

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10 moles of ${C a C O}_{3}$

1 gram atom of Calcium

$6 \times 10^{22}$ atoms of Calcium

$0.1 g$ of Calcium

answer is C.

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Detailed Solution

Using the formula: $moles = \frac{given mass}{molecular mass}$

Molecular weight of calcium carbonate is 100 (Ca=40, C=12, O=16)

Moles of calcium carbonate will be = $\frac{10}{100} = 0.1 m o l e$ = 0.1 g atom.

Since 1mole = $6.022 \times 10^{23}$ atoms

Therefore 0.1mole= $6.022 \times 10^{22}$ atoms of calcium

Hence the correct option is (C).

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