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Q.

10 g of Calcium carbonate contains

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a

10 moles of CaCO3

b

1 gram atom of Calcium

c

6×1022 atoms of Calcium

d

0.1 g of Calcium

answer is C.

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Detailed Solution

 Using the formula: moles=given massmolecular mass

Molecular weight of calcium carbonate is 100 (Ca=40, C=12, O=16)

Moles of calcium carbonate will be = 10100=0.1mole= 0.1 g atom.

Since 1mole = 6.022×1023 atoms

Therefore 0.1mole= 6.022×1022atoms of calcium

Hence the correct option is (C).

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