10 g of Fe3O4 is oxidised completely by 50mL of 0.1M KMnO4 solution. The mass in g of Fe2O3 in Fe3O4 is

meq of Fe2+ inFe3O4=meq of FeO=50×0.1×5=25m mol of FeO= 25 wFeO=25×721000=1.8g wFe2O3=10−1.8=8.2g

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10 g of Fe₃O₄ is oxidised completely by 50mL of 0.1M KMnO₄ solution. The mass in g of Fe₂O₃in Fe₃O₄ is

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Detailed Solution

meq of Fe²⁺ inFe₃O⁴
=meq of $FeO = 50 \times 0.1 \times 5 = 25$
m mol of FeO= 25
$\begin{array}{l} ^{w} FeO = \frac{25 \times 72}{1000} = 1.8 g \\ ^{w} {Fe}_{2} O_{3} = 10 - 1.8 = 8.2 g \end{array}$

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