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10 g of ice at 0°C is mixed with 100 g of water at 50°C. What is the resultant temperature of mixture?

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31.2°C

32.8°C

36.7°C

38:2°c

answer is D.

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Detailed Solution

$10 \times 80 + 10 \times 1 \times (θ - 0) = 100 \times 1 \times (50 - θ) \Rightarrow θ = 38 . 18^{o} C .$

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