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Q.

10 grams of steam at 100°C is mixed with 50 gm of ice at 0°C then final temperature is

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a

50°C

b

100°C

c

20°C

d

40°C

answer is C.

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Detailed Solution

m_sL_s+ m_sS(t_t - t) = m_CL_C + m_CS(t - 0)
(10)(540) + 10(1)(100 - t) = 50(80) + 50(1)(t - 0)
t = 40^o C

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10 grams of steam at 100°C is mixed with 50 gm of ice at 0°C then final temperature is