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10 letter words are formed using the letters $A, B, C, D, E, F, G, H, I, J$ . Let $' x'$ be the number of such words where no letter is repeated and $y$ be the number of words where exactly one letter is repeated twice and no other letter is repeated then

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$x = 10!$

$y = 45 \times 10!$

$y = \frac{10!}{2}$

$x = 45 (10!)$

answer is A, B.

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Detailed Solution

$x = 10!$ $y =^{10} {C_{1}}^{9} C_{8} \frac{10!}{2!}$

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