10 millimoles of solute is present in the following volume of 0.08M solution

$\mathrm{number} \mathrm{of} \mathrm{millimoles}=\mathrm{Molarity} \times \mathrm{volume} \mathrm{in} \mathrm{ml}$

$\mathrm{volume} \mathrm{in} \mathrm{ml}=\frac{\mathrm{number} \mathrm{of} \mathrm{millimoles} }{\mathrm{Molarity}}$=$\frac{10}{0.08}=125 \mathrm{ml}$