10 ml 0.1M $C a {(H C_{2} O_{4})}_{2}$ (assume complete solubility) and 10ml 0.1M $K M n O_{4}$ are mixed in hot acidic solution (oxalate is oxidized to $C O_{2}$ ). Then

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1/4 milli moles $C a (H C_{2} O_{4})$ is left unreacted

1/5 milli mole $K M n O_{4}$ is left unreacted

$K M n O_{4}$ is completely consumed

4 milli moles of $C O_{2}$ is formed

answer is B, C.

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Detailed Solution

No. of meq of $K M n O_{4} = 10 \times 0.1 \times 5 = 5 m e q$

No of meq of $C a {(H C_{2} O_{4})}_{2} = 10 \times 0.1 \times 4 = 4 m e q$

$\underset{4 m e q}{C a {(H C_{2} O_{4})}_{2}} \to \underset{4 m e q}{C O_{2}}$

$4 m e q C O_{2} \Rightarrow 4 m . m o l e s C O_{2}$

$∴ 1 m e q K M n O_{4} i s l e f t \Rightarrow 1 / 5 m . m o l e i s l e f t$

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