10 ml aqueous solution of pure borax requires 3 ml of 0.05 M HCl to reach the end point. Then Mannitol and phenolphthalein indicator are added to the contents left after the first titration. Now it is titrated against 0.1 M NaOH. y ml of NaOH is required to reach the end point. Find ratio of number of millimoles of borax in 10 ml of initial solution to y?

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10 ml aqueous solution of pure borax requires 3 ml of 0.05 M HCl to reach the end point. Then Mannitol and phenolphthalein indicator are added to the contents left after the first titration. Now it is titrated against 0.1 M NaOH. y ml of NaOH is required to reach the end point. Find ratio of number of millimoles of borax in 10 ml of initial solution to y?

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Detailed Solution

One mole borax requires two moles of HCl for neutralization two form four moles of borax. Therefore 4 moles of NaOH are required to neutralize the second step. 10 ml contains 0.15/2 moles of borax which gives 0.3 moles of boric acid. 3 ml of NaOH is required.

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