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10 ml $N_{2}$ is reacted with 20 ml $H_{2}$ to from $N H_{3}$ . The correct statements is /are

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20 ml $N H_{3}$ is formed

13.3 ml $N H_{3}$ is formed

16.7 ml $N H_{3}$ of mixture is left after the completion of the reaction

3.4 ml $N_{2}$ is left after the completion of the reaction

answer is A, C.

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Detailed Solution

20mL of $H_{2} = \frac{2}{3} \times 20 = 13.3 m L o f N H_{3}$

20mL of $H_{2} = \frac{1}{3} \times 20 = 6.6 m L N_{2}$ reacted.

volume of $N_{2}$ unreacted =10ML -6.6 ML=3.4mL

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