10 ml of a gaseous hydrocarbon on combustion gives 40 ml of CO2 gas and 50 ml of H2O vapour at STP. The hydrocarbon is:

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

C4H6

C8H10

C4H8

C4H10

answer is D.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

Concept- Hydrocarbons are compounds comprised exclusively of carbon and hydrogen and they are by far the dominant components of crude oil, processed petroleum hydrocarbons (gasoline, diesel, kerosene, fuel oil, and lubricating oil) , coal tar, creosote, dyestuff, and pyrolysis waste products.
Hydrocarbon on complete combustion gives carbon dioxide

CO 2

gas and
Water vapour

H 2 O

.
The ratio of volumes

= 10 : 40 : 50 = 1 : 4 : 5

All moles of carbon from hydrocarbons are converted into Carbon dioxide.
As

10 ml

of a hydrocarbon produces

40 ml

.
So, from the ratio of volume Hydrocarbon carbon: Carbon dioxide:1:4
So, 1 mole of hydrocarbon has four moles of carbon.
All the hydrogen from hydrocarbons is converted into water.
As10ml of a hydrocarbon produces