10 mL of ${\mathrm{H}}_2{\mathrm{O}}_2$ solution weighs 10 gm. The solution is diluted to 250 mL. 25 mL of of this diluted solution required 40 mL of a M/50 solution of ${\mathrm{KMnO}}_4$ . Then volume strength of original ${\mathrm{H}}_2{\mathrm{O}}_2$ , solution is:

Given : $5{\mathrm{H}}_2{\mathrm{O}}_2+2{\mathrm{KMnO}}_4+6\mathrm{HCl}⟶2\mathrm{KCl}+2{\mathrm{MnCl}}_2+5{\mathrm{O}}_2+8{\mathrm{H}}_2\mathrm{O}$