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Q.

10% (m/m) aqueous potassium iodide has a density of 1.202 g mL-1 . The true statements about this solution are

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a

molarity of this solution is 2.90

b

mole fraction of KI in this solution is 0.0118

c

molality of this solution is 0.67

d

this solution contains 100 g of water

answer is C, D.

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Detailed Solution

10% solution of Kl contains, 10 g of KI in 90 g (or 0.09 kg) of water. 
Molar mass of KI = (39 +127) g mol-1 = 166 g mol-1
molality of solution=Number of moles of KIMass of water (in kg)
                                   =10g/166gmol10.09kg            =0.67molkg1
 Further,Molarity (M)= Moles of KI  Volume of solution(inL
                                 =10g/166gmol1×1000100g/1.202gmL1=10/166×100083.19
[ Volume = Mass / density =100/1.202=83.19mL]
                                                      =0.72molL1=0.72M
 Number of moles of KI=10g166gmol1=0.06mol
 Number of moles of water =90g18gmol1=5mol
 Mole fraction of KI=nKInKI+nH2O
                                =0.065+0.06=0.065.06=0.01186

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