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1.0 molal aqueous solution of an electrolyte X3Y2 is 25% ionized. The boiling point of the solution is : Kb for H2O=0.52Kkg/mol

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a
375.5 K
b
374.04 K
c
377.12 K
d
373.25 K

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detailed solution

Correct option is B

X3Y23X2++2Y3

1α  3α   3α

 i=1+4α=2

ΔTb=2×0.52×1=1.04

 Tb=373+1.04 = 374.04 K

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