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10 mole of $A_{2} B_{3}$ contains $100 g m A$ atom and $60 gm B$ atoms. Choose the correct statements.

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Atomic weight of $A$ is equal to 5

Molecular weight of $A_{2} B_{3}$ is equal to 16

Weight of one atom of $B$ is equal to 2

Atomic weight of $B$ is equal to 6

answer is A, B.

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Detailed Solution

10 moles weighs 160 g and one mole weights 16 g.

$10 \times 2 \times A = 100 \Rightarrow A = 5$

$10 \times 3 \times B = 60 \Rightarrow B = 2$

Hence, options A and B are correct.

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